스프링 데이터 JPA(스프링 부트 없음)
Spring Boot은 Google App Engine과 함께 사용할 수 없습니다(적어도 저에게는 해당되지 않습니다).
GitHub 또는 기타 저장소에서 작성 또는 이용할 수 있는 예제의 대부분은 Spring Boot을 사용하고 있는데, Spring-Data-JPA는 이전과 같이 Spring Boot을 사용하지 않고 플레인 컨텍스트 XML을 사용하는 예가 있습니까?
그러면 알 수 있다
- spring/spring.xml(또는 servlet-spring.xml)
이 예제를 작성했습니다.
src/main/webapp/WEB-INF/spring/context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa.xsd">
<context:property-placeholder location="/WEB-INF/spring/jdbc.properties" />
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.url}"
p:username="${jdbc.username}" p:password="${jdbc.password}" />
<bean id="hibernateJpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
<!-- Configure the entity manager factory bean -->
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="hibernateJpaVendorAdapter" />
<!-- Set JPA properties -->
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
</props>
</property>
<property name="packagesToScan" value="com.demo.data" />
</bean>
<!-- Configure the transaction manager bean -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<tx:annotation-driven />
<jpa:repositories base-package="com.demo.data" />
<context:component-scan base-package="com.demo.svc" />
</beans>
/src/main/webapp/WEB-INF/spring/jdbc.properties
# JDBC Connection
jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.url=jdbc:mysql://host:3306/db
jdbc.username=user
jdbc.password=password
hibernate.dialect=org.hibernate.dialect.MySQLDialect
/src/main/webapp/WEB-INF/spring/servlet-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.demo.web" />
</beans:beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/context.xml</param-value>
</context-param>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>demo_jpa</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
pom.xml
<properties>
<org.springframework-version>4.1.7.RELEASE</org.springframework-version>
<org.hibernate-em-version>4.3.8.Final</org.hibernate-em-version>
<org.springframework.data-version>1.9.0.RELEASE</org.springframework.data-version>
<dbcp-version>1.4</dbcp-version>
<mysql-connector-version>5.1.28</mysql-connector-version>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context-support</artifactId>
<version>${org.springframework-version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>${org.springframework-version}</version>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-jpa</artifactId>
<version>${org.springframework.data-version}</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>${org.hibernate-em-version}</version>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>${mysql-connector-version}</version>
</dependency>
<dependency>
<groupId>commons-dbcp</groupId>
<artifactId>commons-dbcp</artifactId>
<version>${dbcp-version}</version>
</dependency>
</dependencies>
데이터 엔티티: com.demo.data.사용자
package com.demo.data;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;
@Entity
@Table(name = "SYS_USERS")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "USER_ID")
private int id;
@Column(name = "USER_NAME")
private String name;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
스프링 데이터 JPA 저장소: com.demo.data.사용자 저장소
package com.demo.data;
import org.springframework.data.repository.CrudRepository;
public interface UserRepository extends CrudRepository<User, Integer> {
}
서비스
인터페이스:
package com.demo.svc;
import com.demo.data.User;
public interface UserService {
User findUserById(Integer id);
}
구현:
package com.demo.svc;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import com.demo.data.User;
import com.demo.data.UserRepository;
@Service
public class UserServiceImpl implements UserService {
@Autowired
UserRepository userRepository;
public User findUserById(Integer id) {
return userRepository.findOne(id);
}
}
Web 컨트롤러: com.demo.web.사용자 컨트롤러
package com.demo.web;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;
import com.demo.svc.UserService;
@Controller
public class UserController {
@Autowired
UserService svc;
@RequestMapping("/")
@ResponseBody
public String test() {
return svc.findUserById(1).getName();
}
}
이는 컨텍스트에서 UserRepository의 bean을 작성하지 않았기 때문입니다.@Autowired가 UserRepository 클래스에 개체를 삽입하지 않기 때문에 시작 시 컨테이너에 개체를 만들지 않도록 하기 위해 스프링 부트 프로젝트를 사용하지 않기 위해 여러 가지 방법이 있습니다.이 프로젝트의 경우 프로젝트에서 다음을 업데이트할 수 있습니다.
package com.demo.svc;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import com.demo.data.User;
import com.demo.data.UserRepository;
@Service
public class UserServiceImpl implements UserService {
UserRepository userRepository;
public User findUserById(Integer id) {
return userRepository.findOne(id);
}
public UserRepository setRepo(UserRepository repo)
{
userRepository=repo;
}
}
또한 용기에서 물체를 주입해야 합니다.src/main/webapp/WEB-INF/spring/context.xml 내
<bean id="repo" class="com.demo.data.UserRepository"></bean>
<!--Setting the object ref in com.demo.svc.UserServiceImpl-->
<bean id="userserviceImpl" class="com.demo.svc.UserServiceImpl">
<property name="userRepository" ref="repo"></property>
</bean>
도움이 되었으면 좋겠다
이를 추가하면 문제가 해결됩니다.javax.servlet servlet-api 2.5 제공.servlet 3.1(또는 3.0.1)을 사용하는 경우 javax.servlet javax.servlet-api 3.1.0 제공.
언급URL : https://stackoverflow.com/questions/23974249/spring-data-jpa-without-spring-boot
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